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TypeError "is undefined"

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lindaelise View Drop Down
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Joined: 26 Mar 2014
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Post Options Post Options   Quote lindaelise Quote  Post ReplyReply Direct Link To This Post Topic: TypeError "is undefined"
    Posted: 23 Feb 2015 at 8:29pm

I'm hoping someone can help me with a problem I am having with some code I am writing. 

I am getting a TypeError: "is undefined" with the following code:


++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
var srchIndxArr = new Array();

var counter = 0;
for (var i=1; i<global.sV.length; i++) {
  if (typeof global.sV=="undefined") continue;
  t.value = i;
  if (global.sV.sT!=null && global.sV.sT!="") {
 
   
   for (var j in global.sV.sP) {

      var matchesCounter = 1;
      var sP = global.sV.sP[j];
      var mT = global.sV.mT;
      var m = global.sV.m;
     
     //var pR = sPA(global.mainDoc, sP, mT, m, [59,170.0919952392578,594.5,110.5]);
     
      for (var k in global.sV.results) {      
     
       srchIndxArr.push(global.sV.results[k].index);

       var xxx = global.sV.results[k].index;
      
       if (srchIndxArr.indexOf(xxx)!=-1) {
        if (matchesCounter > 1){
         //console.println("no" + matchesCounter);

         } else {
         //console.println("yes" + matchesCounter);

         var pR = sPA(global.mainDoc, sP, mT, m, [59,170.0919952392578,594.5,110.5]);
         }
       matchesCounter = matchesCounter + 1;
      
       } else {
      
       // nothing
      
       }      
         
      }
     
    
         global.sV.results = global.sV.results.concat(pR);
   }
 
  }
 
}

++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++

 

The code in red is what is causing the problem.  Strangely enough, if I moved the code to the location of the green code it does not give me the "is undefined" TypeError.   I want the code to be in the red location because I want variable pR only when matchesCounter is "1" and not more than one.

I've tried moving the code around to see if it made a difference but had no luck. 


I have noticed that putting one "for in" statement inside another "for in" statement seems to cause the problem but I'm wondering if there is more to it than that. The "for in" statements are the following:  "for (var j in global.sV.sP) {"  and " for (var k in global.sV.results) { ".

 

Thanks

Linda

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